From 129f629e10973c31109449dcfad668d5b0bd2190 Mon Sep 17 00:00:00 2001
From: Rabin Osti <117830519+Rabin-Osti@users.noreply.github.com>
Date: Thu, 18 May 2023 23:50:06 +0545
Subject: [PATCH] fix(curriculum): array spread syntax example (#50416)

array literal spread syntax #50414 fixed
---
 ...use-the-spread-operator-to-evaluate-arrays-in-place.md | 8 +++++++-
 1 file changed, 7 insertions(+), 1 deletion(-)

diff --git a/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/es6/use-the-spread-operator-to-evaluate-arrays-in-place.md b/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/es6/use-the-spread-operator-to-evaluate-arrays-in-place.md
index d2aa7189233..a1459ca284e 100644
--- a/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/es6/use-the-spread-operator-to-evaluate-arrays-in-place.md
+++ b/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/es6/use-the-spread-operator-to-evaluate-arrays-in-place.md
@@ -28,7 +28,13 @@ const maximus = Math.max(...arr);
 
 `maximus` would have a value of `89`.
 
-`...arr` returns an unpacked array. In other words, it *spreads* the array. However, the spread operator only works in-place, like in an argument to a function or in an array literal. The following code will not work:
+`...arr` returns an unpacked array. In other words, it spreads the array. However, the spread operator only works in-place, like in an argument to a function or in an array literal. For example:
+
+```js
+const spreaded = [...arr];
+```
+
+However, the following code will not work:
 
 ```js
 const spreaded = ...arr;