diff --git a/curriculum/challenges/english/07-scientific-computing-with-python/learn-interfaces-by-building-an-equation-solver/664ef4623946e65e18d59764.md b/curriculum/challenges/english/07-scientific-computing-with-python/learn-interfaces-by-building-an-equation-solver/664ef4623946e65e18d59764.md
index 645d8aa239a..0b58411dd16 100644
--- a/curriculum/challenges/english/07-scientific-computing-with-python/learn-interfaces-by-building-an-equation-solver/664ef4623946e65e18d59764.md
+++ b/curriculum/challenges/english/07-scientific-computing-with-python/learn-interfaces-by-building-an-equation-solver/664ef4623946e65e18d59764.md
@@ -21,7 +21,7 @@ Modify your regex pattern to use a negative lookbehind so that the character `1`
 
 # --hints--
 
-You should modify the pattern passed as the first argument to the `re.sub()` call using a negative lookbehind. TODO: add details/improve wording
+You should modify the pattern passed as the first argument to the `re.sub()` call using a negative lookbehind.
 
 ```js
 ({ test: () => assert(runPython(`