---
id: 59c3ec9f15068017c96eb8a3
title: Farey sequence
challengeType: 1
forumTopicId: 302266
dashedName: farey-sequence
---
# --description--
The Farey sequence Fn of order `n` is the sequence of completely reduced fractions between `0` and `1` which, when in lowest terms, have denominators less than or equal to `n`, arranged in order of increasing size.
The *Farey sequence* is sometimes incorrectly called a *Farey series*.
Each Farey sequence:
- starts with the value 0, denoted by the fraction $ \frac{0}{1} $
- ends with the value 1, denoted by the fraction $ \frac{1}{1}$.
The Farey sequences of orders `1` to `5` are:
- ${bfit{F}}_1 = frac{0}{1}, frac{1}{1}$
- ${\bf\it{F}}_2 = \frac{0}{1}, \frac{1}{2}, \frac{1}{1}$
- ${\bf\it{F}}_3 = \frac{0}{1}, \frac{1}{3}, \frac{1}{2}, \frac{2}{3}, \frac{1}{1}$
- ${\bf\it{F}}_4 = \frac{0}{1}, \frac{1}{4}, \frac{1}{3}, \frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{1}{1}$
- ${\bf\it{F}}_5 = \frac{0}{1}, \frac{1}{5}, \frac{1}{4}, \frac{1}{3}, \frac{2}{5}, \frac{1}{2}, \frac{3}{5}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}, \frac{1}{1}$
# --instructions--
Write a function that returns the Farey sequence of order `n`. The function should have one parameter that is `n`. It should return the sequence as an array.
# --hints--
`Farey` sollte eine Funktion sein.
```js
assert(typeof farey === 'function');
```
`Farey(3)` sollte ein Array zurückgeben
```js
assert(Array.isArray(farey(3)));
```
`farey(3)` sollte `['0/1','1/3','1/2','2/3','1/1']` zurückgeben
```js
assert.deepEqual(farey(3),['0/1', '1/3', '1/2', '2/3', '1/1']);
```
`farey(4)` sollte `['0/1','1/4','1/3','1/2','2/3','3/4','1/1']` zurückgeben
```js
assert.deepEqual(farey(4), ['0/1', '1/4', '1/3', '1/2', '2/3', '3/4', '1/1']);
```
`farey(5)` sollte `['0/1','1/5','1/4','1/3','2/5','1/2','3/5','2/3','3/4','4/5','1/1']` zurückgeben
```js
assert.deepEqual(farey(5), [
'0/1',
'1/5',
'1/4',
'1/3',
'2/5',
'1/2',
'3/5',
'2/3',
'3/4',
'4/5',
'1/1'
]);
```
# --seed--
## --seed-contents--
```js
function farey(n) {
}
```
# --solutions--
```js
function farey(n) {
const sequence = [{ string: "0/1", float: 0.0 }];
for (let i = 1; i < n; i++) {
for (let j = n; j >= i; j--) {
if (i === 1 || j % i > 0) {
sequence.push({ string: `${i}/${j}`, float: i / j });
}
}
}
return sequence
.sort((a, b) => a.float - b.float)
.map(e => e.string)
}
```