freeCodeCamp/curriculum/challenges/korean/02-javascript-algorithms-and-data-structures/basic-javascript/compound-assignment-with-augmented-division.md

id, title, challengeType, videoUrl, forumTopicId, dashedName

id	title	challengeType	videoUrl	forumTopicId	dashedName
56533eb9ac21ba0edf2244b2	Compound Assignment With Augmented Division	1	https://scrimba.com/c/c2QvKT2	16659	compound-assignment-with-augmented-division

--description--

The /= operator divides a variable by another number.

myVar = myVar / 5;

Will divide myVar by 5. This can be rewritten as:

myVar /= 5;

--instructions--

Convert the assignments for a, b, and c to use the /= operator.

--hints--

a should equal 4.

assert(a === 4);

b should equal 27.

assert(b === 27);

c should equal 3.

assert(c === 3);

You should use the /= operator for each variable.

assert(__helpers.removeJSComments(code).match(/\/=/g).length === 3);

You should not modify the code above the specified comment.

assert(
  /let a = 48;/.test(__helpers.removeJSComments(code)) &&
    /let b = 108;/.test(__helpers.removeJSComments(code)) &&
    /let c = 33;/.test(__helpers.removeJSComments(code))
);

--seed--

--after-user-code--

(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);

--seed-contents--

let a = 48;
let b = 108;
let c = 33;

// Only change code below this line
a = a / 12;
b = b / 4;
c = c / 11;

--solutions--

let a = 48;
let b = 108;
let c = 33;

a /= 12;
b /= 4;
c /= 11;