freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/i-before-e-except-after-c.md

id, title, challengeType, forumTopicId, dashedName

id	title	challengeType	forumTopicId	dashedName
5a23c84252665b21eecc7eb0	I 在 E 之前，除了 C 之后	1	302288	i-before-e-except-after-c

--description--

"I before E, except after C" is a general rule for English language spelling. If one is unsure whether a word is spelled with the digraph ei or ie, the rhyme suggests that the correct order is ie unless the preceding letter is c, in which case it may be ei.

Using the words provided, check if the two sub-clauses of the phrase are plausible individually:

1. "I before E when not preceded by C".
2. "E before I when preceded by C".

如果两个子短语都是合理的，则原始短语可以说是合理的。

--instructions--

Write a function that accepts a word and check if the word follows this rule. The function should return true if the word follows the rule and false if it does not.

--hints--

IBeforeExceptC 应该是一个函数。

assert(typeof IBeforeExceptC == 'function');

IBeforeExceptC("receive") 应该返回一个布尔值。

assert(typeof IBeforeExceptC('receive') == 'boolean');

IBeforeExceptC("receive") 应该返回 true。

assert.equal(IBeforeExceptC('receive'), true);

IBeforeExceptC("science") 应该返回 false。

assert.equal(IBeforeExceptC('science'), false);

IBeforeExceptC("imperceivable") 应该返回 true。

assert.equal(IBeforeExceptC('imperceivable'), true);

IBeforeExceptC("inconceivable") 应该返回 true。

assert.equal(IBeforeExceptC('inconceivable'), true);

IBeforeExceptC("insufficient") 应该返回 false.

assert.equal(IBeforeExceptC('insufficient'), false);

IBeforeExceptC("omniscient") 应该返回 false.

assert.equal(IBeforeExceptC('omniscient'), false);

--seed--

--seed-contents--

function IBeforeExceptC(word) {

}

--solutions--

function IBeforeExceptC(word)
{
    if(word.indexOf("c")==-1 && word.indexOf("ie")!=-1)
        return true;
    else if(word.indexOf("cei")!=-1)
        return true;
    return false;
}