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Co-authored-by: Kolade Chris <65571316+Ksound22@users.noreply.github.com> Co-authored-by: Huyen Nguyen <25715018+huyenltnguyen@users.noreply.github.com>
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id, title, challengeType, dashedName
| id | title | challengeType | dashedName |
|---|---|---|---|
| 681cb1b0dab50c87ddb2e51b | JavaScript Challenge 10: 3 Strikes | 28 | javascript-challenge-10 |
--description--
Given an integer between 1 and 10,000, return a count of how many numbers from 1 up to that integer whose square contains at least one digit 3.
--hints--
squaresWithThree(1) should return 0.
assert.equal(squaresWithThree(1), 0);
squaresWithThree(10) should return 1.
assert.equal(squaresWithThree(10), 1);
squaresWithThree(100) should return 19.
assert.equal(squaresWithThree(100), 19);
squaresWithThree(1000) should return 326.
assert.equal(squaresWithThree(1000), 326);
squaresWithThree(10000) should return 4531.
assert.equal(squaresWithThree(10000), 4531);
--seed--
--seed-contents--
function squaresWithThree(n) {
return n;
}
--solutions--
function squaresWithThree(n) {
let count = 0;
for (let i = 1; i <= n; i++) {
const square = i * i;
if (square.toString().includes('3')) {
count++;
}
}
return count;
}