freeCodeCamp/curriculum/challenges/english/99-dev-playground/daily-coding-challenges-python/python-challenge-1.md

id, title, challengeType, dashedName

id	title	challengeType	dashedName
6814d93d516e86b171929de5	Python Challenge 1: Vowel Balance	29	python-challenge-1

--description--

Given a string, determine whether the number of vowels in the first half of the string is equal to the number of vowels in the second half.

• The string can contain any characters.
• The letters a, e, i, o, and u, in either uppercase or lowercase, are considered vowels.
• If there's an odd number of characters in the string, ignore the center character.

--hints--

is_balanced("racecar") should return True.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertTrue(is_balanced("racecar"))`)
}})

is_balanced("Lorem Ipsum") should return True.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertTrue(is_balanced("Lorem Ipsum"))`)
}})

is_balanced("Kitty Ipsum") should return False.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertFalse(is_balanced("Kitty Ipsum"))`)
}})

is_balanced("string") should return False.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertFalse(is_balanced("string"))`)
}})

is_balanced(" ") should return True.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertTrue(is_balanced(" "))`)
}})

is_balanced("abcdefghijklmnopqrstuvwxyz") should return False.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertFalse(is_balanced("abcdefghijklmnopqrstuvwxyz"))`)
}})

is_balanced("123A#b!E&*456-o.U") should return True.

({test: () => { runPython(`
from unittest import TestCase
TestCase().assertTrue(is_balanced("123A#b!E&*456-o.U"))`)
}})

--seed--

--seed-contents--

def is_balanced(s):

    return s

--solutions--

def is_balanced(s):
    vowels = set("aeiouAEIOU")
    n = len(s)
    half = n // 2

    first_half = s[:half]
    second_half = s[-half:]

    def count_vowels(sub):
        return sum(1 for char in sub if char in vowels)

    return count_vowels(first_half) == count_vowels(second_half)