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For files that have a Cloudera copyright (and no other copyright notice), make changes to follow the ASF source file header policy here: http://www.apache.org/legal/src-headers.html#headers Specifically: 1) Remove the Cloudera copyright. 2) Modify NOTICE.txt according to http://www.apache.org/legal/src-headers.html#notice to follow that format and add a line for Cloudera. 3) Replace or add the existing ASF license text with the one given on the website. Much of this change was automatically generated via: git grep -li 'Copyright.*Cloudera' > modified_files.txt cat modified_files.txt | xargs perl -n -i -e 'print unless m#Copyright.*Cloudera#i;' cat modified_files_txt | xargs fix_apache_license.py [1] Some manual fixups were performed following those steps, especially when license text was completely missing from the file. [1] https://gist.github.com/anonymous/ff71292094362fc5c594 with minor modification to ORIG_LICENSE to match Impala's license text. Change-Id: I2e0bd8420945b953e1b806041bea4d72a3943d86 Reviewed-on: http://gerrit.cloudera.org:8080/3779 Reviewed-by: Dan Hecht <dhecht@cloudera.com> Tested-by: Internal Jenkins
46 lines
1.7 KiB
Python
Executable File
46 lines
1.7 KiB
Python
Executable File
#!/usr/bin/python
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#
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# Licensed to the Apache Software Foundation (ASF) under one
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# or more contributor license agreements. See the NOTICE file
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# distributed with this work for additional information
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# regarding copyright ownership. The ASF licenses this file
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# to you under the Apache License, Version 2.0 (the
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# "License"); you may not use this file except in compliance
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# with the License. You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing,
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# software distributed under the License is distributed on an
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# "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
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# KIND, either express or implied. See the License for the
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# specific language governing permissions and limitations
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# under the License.
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# This script finds Python 2.6 or higher on the system and outputs the
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# system command to stdout. The script exits with a nonzero exit code if
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# Python 2.6+ is not present.
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import os
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import subprocess
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import sys
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import textwrap
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def detect_python_cmd():
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'''Returns the system command that provides python 2.6 or greater.'''
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paths = os.getenv("PATH").split(os.path.pathsep)
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for cmd in ("python", "python27", "python2.7", "python-27", "python-2.7", "python26",
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"python2.6", "python-26", "python-2.6"):
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for path in paths:
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cmd_path = os.path.join(path, cmd)
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if not os.path.exists(cmd_path) or not os.access(cmd_path, os.X_OK):
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continue
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exit = subprocess.call([cmd_path, "-c", textwrap.dedent("""
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import sys
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sys.exit(int(sys.version_info[:2] < (2, 6)))""")])
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if exit == 0:
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return cmd_path
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raise Exception("Could not find minimum required python version 2.6")
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print detect_python_cmd()
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