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16
curriculum/challenges/arabic/02-javascript-algorithms-and-data-structures/basic-javascript/comparison-with-the-less-than-operator.md
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@@ -9,7 +9,7 @@ dashedName: comparison-with-the-less-than-operator
# --description--
يقارن مشغل آلأصغر من (`<`) بين قيمتين رقمين. إذا كان الرَّقَم إلى اليسار أصغر من الرَّقَم إلى اليمين، فإنه يرجع `true`. خلاف ذلك، فإنه يرجع `false`. وعلى غرار المشغل المعني بالمساواة، يقوم المشغل أقل من بتحويل أنواع البيانات عند مقارنتها.
يقارن مشغل الأصغر من (`<`) بين قيم رقمين. إذا كان الرَّقَم إلى اليسار أصغر من الرَّقَم إلى اليمين، فإنه يرجع `true`. خلاف ذلك، فإنه يرجع `false`. وعلى غرار مشغل المساواة، يقوم المشغل أقل من بتحويل أنواع البيانات عند مقارنتها.
**مثال**
@@ -23,41 +23,41 @@ dashedName: comparison-with-the-less-than-operator
# --instructions--
أضف مشغل أقل من إلى الخطوط المشار إليها بحيث تكون تعبيرات مراجعة منطقية.
أضف مشغل أقل من إلى الخطوط المشار إليها بحيث تكون تعبيرات return منطقية.
# --hints--
يجب أن ينتج `testLessThan(0)` مقطع `Under 25`
يجب أن ينتج `testLessThan(0)` المقطع النصي `Under 25`
```js
assert(testLessThan(0) === 'Under 25');
```
يجب أن ينتج `testLessThan(24)` مقطع `Under 25`
يجب أن ينتج `testLessThan(24)` المقطع النصي `Under 25`
```js
assert(testLessThan(24) === 'Under 25');
```
يجب أن ينتج `testLessThan(25)` مقطع `Under 55`
يجب أن ينتج `testLessThan(25)` المقطع النصي `Under 55`
```js
assert(testLessThan(25) === 'Under 55');
```
يجب أن ينتج `testLessThan(54)` مقطع `Under 55`
يجب أن ينتج `testLessThan(54)` المقطع النصي `Under 55`
```js
assert(testLessThan(54) === 'Under 55');
```
يجب أن ينتج `testLessThan(55)` مقطع `55 or Over`
يجب أن ينتج `testLessThan(55)` المقطع النصي `55 or Over`
```js
assert(testLessThan(55) === '55 or Over');
```
يجب أن ينتج `testLessThan(99)` مقطع `55 or Over`
يجب أن ينتج `testLessThan(99)` المقطع النصي `55 or Over`
```js
assert(testLessThan(99) === '55 or Over');

18
curriculum/challenges/arabic/02-javascript-algorithms-and-data-structures/basic-javascript/comparison-with-the-less-than-or-equal-to-operator.md
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@@ -9,7 +9,7 @@ dashedName: comparison-with-the-less-than-or-equal-to-operator
# --description--
مشغل اصغر من أو يساوي، (`<=`) يقارن بين قيم رقمين. إذا كان الرَّقَم إلى اليسار أقل من أو يساوي الرَّقَم إلى اليمين، فإنه يعيد `true`. إذا كان الرَّقَم الموجود على اليسار أكبر من الرَّقَم الموجود على اليمين، فإنه يعيد `false`. وعلى غرار المشغل المعني بالمساواة، يحول مشغل اصغر من أو يساوي أنواع البيانات من القيم عند مقارنتها.
مشغل اصغر من أو يساوي، (`<=`) يقارن بين قيم رقمين. إذا كان الرَّقَم إلى اليسار أقل من أو يساوي الرَّقَم إلى اليمين، فإنه يعيد `true`. إذا كان الرَّقَم الموجود على اليسار أكبر من الرَّقَم الموجود على اليمين، فإنه يعيد `false`. وعلى غرار مشغل المساواة، يحول مشغل اصغر من أو يساوي أنواع البيانات عند مقارنتها.
**مثال**
@@ -23,47 +23,47 @@ dashedName: comparison-with-the-less-than-or-equal-to-operator
# --instructions--
أضف مشغل اصغر من أو يساوي إلى السطور المشار إليها بحيث تكون تعبيرات المراجعة منطقية.
أضف مشغل اصغر من أو يساوي إلى السطور المشار إليها بحيث تكون تعبيرات return منطقية.
# --hints--
يجب أن ينتج `testLessOrEqual(0)` المقطع `Smaller Than or Equal to 12`
يجب أن ينتج `testLessOrEqual(0)` المقطع النصي `Smaller Than or Equal to 12`
```js
assert(testLessOrEqual(0) === 'Smaller Than or Equal to 12');
```
يجب أن ينتج `testLessOrEqual(11)` مقطع `Smaller Than or Equal to 12`
يجب أن ينتج `testLessOrEqual(11)` المقطع النصي `Smaller Than or Equal to 12`
```js
assert(testLessOrEqual(11) === 'Smaller Than or Equal to 12');
```
يجب أن ينتج `testLessOrEqual(12)` مقطع `Smaller Than or Equal to 12`
يجب أن ينتج `testLessOrEqual(12)` المقطع النصي `Smaller Than or Equal to 12`
```js
assert(testLessOrEqual(12) === 'Smaller Than or Equal to 12');
```
يجب أن ينتج `testLessOrEqual(23)` مقطع `Smaller Than or Equal to 24`
يجب أن ينتج `testLessOrEqual(23)` المقطع النصي `Smaller Than or Equal to 24`
```js
assert(testLessOrEqual(23) === 'Smaller Than or Equal to 24');
```
يجب أن ينتج `testLessOrEqual(24)` مقطع `Smaller Than or Equal to 24`
يجب أن ينتج `testLessOrEqual(24)` المقطع النصي `Smaller Than or Equal to 24`
```js
assert(testLessOrEqual(24) === 'Smaller Than or Equal to 24');
```
يجب أن ينتج `testLessOrEqual(25)` مقطع `More Than 24`
يجب أن ينتج `testLessOrEqual(25)` المقطع النصي `More Than 24`
```js
assert(testLessOrEqual(25) === 'More Than 24');
```
يجب أن ينتج `testLessOrEqual(55)` مقطع `More Than 24`
يجب أن ينتج `testLessOrEqual(55)` المقطع النصي `More Than 24`
```js
assert(testLessOrEqual(55) === 'More Than 24');

22
curriculum/challenges/arabic/02-javascript-algorithms-and-data-structures/basic-javascript/comparisons-with-the-logical-and-operator.md
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@@ -11,7 +11,7 @@ dashedName: comparisons-with-the-logical-and-operator
ستحتاج أحيانًا إلى اختبار أكثر من شيء في وقت واحد. مشغل <dfn>الإضافة المنطقي</dfn> ورمزه (`&&`) يرجع `true` فقط إذا كان <dfn>المعاملتين</dfn> إلى اليسار واليمين صحيحين.
ويمكن تحقيق نفس التأثير عن طريق أدخال if statement داخل if أخري:
ويمكن تحقيق نفس التأثير عن طريق وضع عبارة if داخل if أخري:
```js
if (num > 5) {
@@ -33,7 +33,7 @@ return "No";
# --instructions--
استبدل بيانين if إلى if statement واحدة، باستخدام المشغل `&&`، الذي سوف يعيد المقطع `Yes` إذا كان `val` أقل من أو يساوي `50` وأكثر من أو يساوي `25`. خلاف ذلك، سوف يعيد المقطع `No`.
استبدل العبارتان if إلى if واحدة، باستخدام المشغل `&&`، الذي سوف يعيد المقطع `Yes` إذا كان `val` أقل من أو يساوي `50` وأكثر من أو يساوي `25`. خلاف ذلك، سوف يعيد المقطع `No`.
# --hints--
@@ -43,55 +43,55 @@ return "No";
assert(code.match(/&&/g).length === 1);
```
يجب أن يكون لديك بيان `if` واحد فقط
يجب أن يكون لديك عبارة `if` واحد فقط
```js
assert(code.match(/if/g).length === 1);
```
يجب أن ينتج `testLogicalAnd(0)` مقطع `No`
يجب أن ينتج `testLogicalAnd(0)` المقطع النصي `No`
```js
assert(testLogicalAnd(0) === 'No');
```
يجب أن ينتج `testLogicalAnd(24)` المقطع `No`
يجب أن ينتج `testLogicalAnd(24)` المقطع النصي `No`
```js
assert(testLogicalAnd(24) === 'No');
```
يجب أن ينتج `testLogicalAnd(25)` المقطع `Yes`
يجب أن ينتج `testLogicalAnd(25)` المقطع النصي `Yes`
```js
assert(testLogicalAnd(25) === 'Yes');
```
يجب أن ينتج `testLogicalAnd(30)` المقطع `Yes`
يجب أن ينتج `testLogicalAnd(30)` المقطع النصي `Yes`
```js
assert(testLogicalAnd(30) === 'Yes');
```
يجب أن ينتج `testLogicalAnd(50)` المقطع `Yes`
يجب أن ينتج `testLogicalAnd(50)` المقطع النصي `Yes`
```js
assert(testLogicalAnd(50) === 'Yes');
```
يجب أن ينتج `testLogicalAnd(51)` المقطع `No`
يجب أن ينتج `testLogicalAnd(51)` المقطع النصي `No`
```js
assert(testLogicalAnd(51) === 'No');
```
يجب أن ينتج `testLogicalAnd(75)` المقطع `No`
يجب أن ينتج `testLogicalAnd(75)` المقطع النصي `No`
```js
assert(testLogicalAnd(75) === 'No');
```
يجب أن ينتج `testLogicalAnd(80)` المقطع `No`
يجب أن ينتج `testLogicalAnd(80)` المقطع النصي `No`
```js
assert(testLogicalAnd(80) === 'No');

6
curriculum/challenges/arabic/02-javascript-algorithms-and-data-structures/basic-javascript/comparisons-with-the-logical-or-operator.md
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@@ -1,6 +1,6 @@
---
id: 56533eb9ac21ba0edf2244d9
title: المقارنات باستخدام مشغل إي من المنطقي
title: المقارنات باستخدام مشغل إي من (or) المنطقي (||)
challengeType: 1
videoUrl: 'https://scrimba.com/c/cEPrGTN'
forumTopicId: 16800
@@ -9,9 +9,9 @@ dashedName: comparisons-with-the-logical-or-operator
# --description--
يرجع مشغل <dfn>إي من</dfn> الآتي (`||`) القيمة `true` إذا كان أي من <dfn>المعاملتين</dfn> هما `true`. خلاف ذلك، فإنه يرجع `false`.
يرجع مشغل <dfn>إي من</dfn> (logical or) الآتي (`||`) القيمة `true` إذا كان أي من <dfn>المعاملتين</dfn> هما `true`. خلاف ذلك، فإنه يرجع `false`.
يتكون مشغل <dfn>المعاملات</dfn> من رمزين و هما خطين مستقيمين ألآتيه: (`||`). يمكن العثور على هذا الرمز عادة بين مفاتيح Backspace و Enter.
يتكون مشغل <dfn>إي من</dfn> من رمزين و هما خطين مستقيمين كالآتي: (`||`). يمكن العثور على هذا الرمز عادة بين مفاتيح Backspace و Enter.
يجب أن يبدو النمط أدناه مألوفًا من الدروس السابقة:

14
curriculum/challenges/espanol/16-the-odin-project/top-build-a-recipe-project/top-build-a-recipe-project.md
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@@ -1,20 +1,20 @@
---
id: 6391d1a4f7ac71efd0621380
title: Build a Recipe Page Project
title: Construir un proyecto de página de recetas
challengeType: 14
dashedName: top-build-a-recipe-project
---
# --description--
The website will consist of a main index page which will have links to a few recipes. The website won’t look very pretty by the time you’ve finished.
El sitio web constará de una página de índice principal que tendrá enlaces a algunas recetas. La página web no será muy bonita para cuando haya terminado.
**User Stories:**
**Historias de usuario:**
1. Your recipe page should contain a `DOCTYPE` tag.
1. Your recipe page should include an `html` element with a `head` and `body` element as children.
1. You should have a `title` element within the `head` element with the text `The Odin Recipes`.
1. You should see an `h1` element that has the text `Creamy Chocolate Fudge`.
1. La página de tu receta debe contener una etiqueta `DOCTYPE`.
1. Tu página de receta debe incluir un elemento `html` con un elemento `head` y `body` como hijos.
1. Debes tener un elemento `title` dentro del elemento `head` con el texto <codeThe Odin Recipes</code>.
1. Deberías ver un elemento `h1` que tiene el texto `Creamy Chocolate Fudge`.
1. You should see an image with the url `*placeholder-fcc-cdn*` with a fitting `alt` text.
1. There should be an `h2` element with the text `Description` under the image.
1. You should see a couple of paragraphs under `Description` that describe the recipe.

14
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-449-chocolate-covered-candy.md
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@@ -1,6 +1,6 @@
---
id: 5900f52d1000cf542c510040
title: 'Problem 449: Chocolate covered candy'
title: 'Problem 449: Mit Schokolade überzogene Süßigkeiten'
challengeType: 1
forumTopicId: 302121
dashedName: problem-449-chocolate-covered-candy
@@ -8,19 +8,19 @@ dashedName: problem-449-chocolate-covered-candy
# --description--
Phil the confectioner is making a new batch of chocolate covered candy. Each candy centre is shaped like an ellipsoid of revolution defined by the equation: $b^2x^2 + b^2y^2 + a^2z^2 = a^2b^2$.
Phil, der Konditor, stellt eine neue Ladung schokoladenüberzogener Süßigkeiten her. Jedes Herzstück der Süßigkeiten hat die Form eines Ellipsoids, das durch die folgende Gleichung definiert ist: $b^2x^2 + b^2y^2 + a^2z^2 = a^2b^2$.
Phil wants to know how much chocolate is needed to cover one candy centre with a uniform coat of chocolate one millimeter thick.
Phil möchte wissen, wie viel Schokolade benötigt wird, um das Herzstück mit einer gleichmäßigen Schokoladenschicht von einem Millimeter Dicke zu überziehen.
If $a = 1$ mm and $b = 1$ mm, the amount of chocolate required is $\frac{28}{3} \pi$ mm<sup>3</sup>
Wenn $a = 1$ mm und $b = 1$ mm ist, beträgt die benötigte Menge an Schokolade $\frac{28}{3} \pi$ mm<sup>3</sup>
If $a = 2$ mm and $b = 1$ mm, the amount of chocolate required is approximately 60.35475635 mm<sup>3</sup>.
Wenn $a = 2$ mm und $b = 1$ mm ist, beträgt die benötigte Schokoladenmenge ungefähr 60,35475635 mm<sup>3</sup>.
Find the amount of chocolate in mm<sup>3</sup> required if $a = 3$ mm and $b = 1$ mm. Give your answer as the number rounded to 8 decimal places behind the decimal point.
Ermittle die Menge an Schokolade in mm<sup>3</sup>, die benötigt wird, wenn $a = 3$ mm und $b = 1$ mm ist. Gib deine Antwort als Zahl an, die auf 8 Dezimalstellen hinter dem Komma gerundet ist.
# --hints--
`chocolateCoveredCandy()` should return `103.37870096`.
`chocolateCoveredCandy()` sollte `103.37870096` zurückgeben.
```js
assert.strictEqual(chocolateCoveredCandy(), 103.37870096);

20
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-450-hypocycloid-and-lattice-points.md
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@@ -1,6 +1,6 @@
---
id: 5900f52e1000cf542c510041
title: 'Problem 450: Hypocycloid and Lattice points'
title: 'Problem 450: Hypozykloide und Gitterpunkte'
challengeType: 1
forumTopicId: 302123
dashedName: problem-450-hypocycloid-and-lattice-points
@@ -8,36 +8,36 @@ dashedName: problem-450-hypocycloid-and-lattice-points
# --description--
A hypocycloid is the curve drawn by a point on a small circle rolling inside a larger circle. The parametric equations of a hypocycloid centered at the origin, and starting at the right most point is given by:
Eine Hypozykloide ist die Kurve, die von einem Punkt auf einem kleinen Kreis gezeichnet wird, der sich innerhalb eines größeren Kreises bewegt. Die Parametergleichungen einer Hypozykloide, die im Ursprung zentriert ist und im äußersten rechten Punkt beginnt, sind gegeben durch:
$$x(t) = (R - r) \cos(t) + r \cos(\frac{R - r}{r}t)$$
$$y(t) = (R - r) \sin(t) - r \sin(\frac{R - r}{r} t)$$
Where $R$ is the radius of the large circle and $r$ the radius of the small circle.
Dabei ist $R$ der Radius des großen Kreises und $r$ der Radius des kleinen Kreises.
Let $C(R, r)$ be the set of distinct points with integer coordinates on the hypocycloid with radius $R$ and $r$ and for which there is a corresponding value of $t$ such that $\sin(t)$ and $\cos(t)$ are rational numbers.
Lasse $C(R, r)$ die Menge der verschiedenen Punkte mit ganzzahligen Koordinaten auf der Hypozykloide mit Radius $R$ und $r$ sein, für die es einen entsprechenden Wert von $t$ gibt, sodass $\sin(t)$ und $\cos(t)$ rationale Zahlen sind.
Let $S(R, r) = \sum\_{(x,y) \in C(R, r)} |x| + |y|$ be the sum of the absolute values of the $x$ and $y$ coordinates of the points in $C(R, r)$.
Lasse $S(R, r) = \sum\_{(x,y) \in C(R, r)} |x| + |y|$ die Summe der Absolutwerte der $x$ und $y$ Koordinaten der Punkte in $C(R, r)$ sein.
Let $T(N) = \sum_{R = 3}^N \sum_{r=1}^{\left\lfloor \frac{R - 1}{2} \right\rfloor} S(R, r)$ be the sum of $S(R, r)$ for $R$ and $r$ positive integers, $R\leq N$ and $2r &lt; R$.
Lasse $T(N) = \sum_{R = 3}^N \sum_{r=1}^{\left\lfloor \frac{R - 1}{2} \right\rfloor} S(R, r)$ die Summe von $S(R, r)$ für $R$ und $r$ positive ganze Zahlen, $R\leq N$ und $2r &lt; R$ sein.
You are given:
Folgendes ist gegeben:
$$\begin{align} C(3, 1) = & \\{(3, 0), (-1, 2), (-1,0), (-1,-2)\\} \\\\
C(2500, 1000) = & \\{(2500, 0), (772, 2376), (772, -2376), (516, 1792), (516, -1792), (500, 0), (68, 504), \\\\ &(68, -504),(-1356, 1088), (-1356, -1088), (-1500, 1000), (-1500, -1000)\\} \end{align}$$
**Note:** (-625, 0) is not an element of $C(2500, 1000)$ because $\sin(t)$ is not a rational number for the corresponding values of $t$.
**Hinweis:** (-625, 0) ist kein Element von $C(2500, 1000)$, weil $\sin(t)$ keine rationale Zahl für die entsprechenden Werte von $t$ ist.
$S(3, 1) = (|3| + |0|) + (|-1| + |2|) + (|-1| + |0|) + (|-1| + |-2|) = 10$
$T(3) = 10$; $T(10) = 524$; $T(100) = 580\\,442$; $T({10}^3) = 583\\,108\\,600$.
Find $T({10}^6)$.
Finde $T({10}^6)$.
# --hints--
`hypocycloidAndLatticePoints()` should return `583333163984220900`.
`hypocycloidAndLatticePoints()` sollte `583333163984220900` zurückgeben.
```js
assert.strictEqual(hypocycloidAndLatticePoints(), 583333163984220900);

18
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-451-modular-inverses.md
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@@ -1,6 +1,6 @@
---
id: 5900f5311000cf542c510042
title: 'Problem 451: Modular inverses'
title: 'Problem 451: Modularer Kehrwert'
challengeType: 1
forumTopicId: 302124
dashedName: problem-451-modular-inverses
@@ -8,28 +8,28 @@ dashedName: problem-451-modular-inverses
# --description--
Consider the number 15.
Betrachten wir die Zahl 15.
There are eight positive numbers less than 15 which are coprime to 15: 1, 2, 4, 7, 8, 11, 13, 14.
Es gibt acht positive Zahlen kleiner als 15 sind, die zu 15 koprimiert sind: 1, 2, 4, 7, 8, 11, 13, 14.
The modular inverses of these numbers modulo 15 are: 1, 8, 4, 13, 2, 11, 7, 14 because
Der modulare Kehrwert dieser modulen Zahlen 15 sind: 1, 8, 4, 13, 2, 11, 7, 14, denn
$$\begin{align} & 1 \times 1\bmod 15 = 1 \\\\
& 2 \times 8 = 16\bmod 15 = 1 \\\\ & 4 \times 4 = 16\bmod 15 = 1 \\\\
& 7 \times 13 = 91\bmod 15 = 1 \\\\ & 11 \times 11 = 121\bmod 15 = 1 \\\\
& 14 \times 14 = 196\bmod 15 = 1 \end{align}$$
Let $I(n)$ be the largest positive number $m$ smaller than $n - 1$ such that the modular inverse of $m$ modulo $n$ equals $m$ itself.
Lasse $I(n)$ die größte positive Zahl $m$ kleiner als $n - 1$ sein, sodass der modulare Kehrwert von $m$ modulo $n$ gleich $m$ ist.
So $I(15) = 11$.
Somit ist $I(15) = 11$.
Also $I(100) = 51$ and $I(7) = 1$.
Außerdem $I(100) = 51$ und $I(7) = 1$.
Find $\sum I(n)$ for $3 ≤ n ≤ 2 \times {10}^7$
Finde $\sum l(n)$ für $3 ≤ n ≤ 2 \times {10}^7$
# --hints--
`modularInverses()` should return `153651073760956`.
`modularInverses()` sollte `153651073760956` zurückgeben.
```js
assert.strictEqual(modularInverses(), 153651073760956);

8
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-452-long-products.md
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@@ -8,17 +8,17 @@ dashedName: problem-452-long-products
# --description--
Define $F(m, n)$ as the number of $n$-tuples of positive integers for which the product of the elements doesn't exceed $m$.
Definiere $F(m, n)$ als die Anzahl der Variablen $n$ aus positiven Integer, bei denen das Produkt der Elemente $m$ nicht überschreitet.
$F(10, 10) = 571$.
$F({10}^6, {10}^6)\bmod 1\\,234\\,567\\,891 = 252\\,903\\,833$.
$F({10}^6, {10}^6)\bmod 1\,234\,567\,891 = 252\,903\,833$.
Find $F({10}^9, {10}^9)\bmod 1\\,234\\,567\\,891$.
Finde $F({10}^9, {10}^9)\bmod 1\\,234\\,567\\,891$.
# --hints--
`longProducts()` should return `345558983`.
`longProducts()` sollte `345558983` zurückgeben.
```js
assert.strictEqual(longProducts(), 345558983);

16
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-453-lattice-quadrilaterals.md
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@@ -1,6 +1,6 @@
---
id: 5900f5311000cf542c510044
title: 'Problem 453: Lattice Quadrilaterals'
title: 'Problematik 453: Quadrilaterale Gitter'
challengeType: 1
forumTopicId: 302126
dashedName: problem-453-lattice-quadrilaterals
@@ -8,21 +8,21 @@ dashedName: problem-453-lattice-quadrilaterals
# --description--
A simple quadrilateral is a polygon that has four distinct vertices, has no straight angles and does not self-intersect.
Ein einfaches Viereck ist ein Vieleck, das vier verschiedene Eckpunkte hat, keine geraden Winkel aufweist und sich nicht selbst schneidet.
Let $Q(m, n)$ be the number of simple quadrilaterals whose vertices are lattice points with coordinates ($x$, $y$) satisfying $0 ≤ x ≤ m$ and $0 ≤ y ≤ n$.
Lasse $Q(m, n)$ die Anzahl der einfachen Vierecke sein, deren Eckpunkte Gitterpunkte mit Koordinaten ($x$, $y$) sind, die $0 ≤ x ≤ m$ und $0 ≤ y ≤ n$ erfüllen.
For example, $Q(2, 2) = 94$ as can be seen below:
Zum Beispiel $Q(2, 2) = 94$, wie unten zu sehen ist:
<img class="img-responsive center-block" alt="94 quadrilaterals whose vertices are lattice points with coordinates (x, y) satiffying 0 &le; x &le; m and 0 &le; y &le; n" src="https://cdn.freecodecamp.org/curriculum/project-euler/lattice-quadrilaterals.png" style="background-color: white; padding: 10px;" />
<img class="img-responsive center-block" alt="94 Vierecke, deren Eckpunkte Gitterpunkte mit Koordinaten (x, y) sind, die 0 &le; x &le; m und 0 &le; y &le; n genügen" src="https://cdn.freecodecamp.org/curriculum/project-euler/lattice-quadrilaterals.png" style="background-color: white; padding: 10px;" />
It can also be verified that $Q(3, 7) = 39\\,590$, $Q(12, 3) = 309\\,000$ and $Q(123, 45) = 70\\,542\\,215\\,894\\,646$.
Es lässt sich auch nachweisen, dass $Q(3, 7) = 39\\,590$, $Q(12, 3) = 309\\,000$ und $Q(123, 45) = 70\\,542\\,215\\,894\\,646$.
Find $Q(12\\,345, 6\\,789)\bmod 135\\,707\\,531$.
Finde $Q(12\\,345, 6\\,789)\bmod 135\\,707\\,531$.
# --hints--
`latticeQuadrilaterals()` should return `104354107`.
`latticeQuadrilaterals()` sollte `104354107` zurückgeben.
```js
assert.strictEqual(latticeQuadrilaterals(), 104354107);

12
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-454-diophantine-reciprocals-iii.md
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---
id: 5900f5331000cf542c510045
title: 'Problem 454: Diophantine reciprocals III'
title: 'Problematik 454: Diophantische Kehrwerte III'
challengeType: 1
forumTopicId: 302127
dashedName: problem-454-diophantine-reciprocals-iii
@@ -8,19 +8,19 @@ dashedName: problem-454-diophantine-reciprocals-iii
# --description--
In the following equation $x$, $y$, and $n$ are positive integers.
In der folgenden Gleichung $x$, $y$, und $n$ gibt es positive Integer.
$$\frac{1}{x} + \frac{1}{y} = \frac{1}{n}$$
For a limit $L$ we define $F(L)$ as the number of solutions which satisfy $x &lt; y ≤ L$.
Für einen Grenzwert $L$ definieren wir $F(L)$ als die Anzahl der Lösungen, die $x &lt; y ≤ L$ erfüllen.
We can verify that $F(15) = 4$ and $F(1000) = 1069$.
Wir können überprüfen, dass $F(15) = 4$ und $F(1000) = 1069$.
Find $F({10}^{12})$.
Finde $F({10}^{12})$.
# --hints--
`diophantineReciprocalsThree()` should return `5435004633092`.
`diophantineReciprocalsThree()` sollte `5435004633092` zurückgeben.
```js
assert.strictEqual(diophantineReciprocalsThree(), 5435004633092);

10
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-455-powers-with-trailing-digits.md
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---
id: 5900f5331000cf542c510046
title: 'Problem 455: Powers With Trailing Digits'
title: 'Problem 455: Potenzen mit nachgestellten Ziffern'
challengeType: 1
forumTopicId: 302129
dashedName: problem-455-powers-with-trailing-digits
@@ -8,19 +8,19 @@ dashedName: problem-455-powers-with-trailing-digits
# --description--
Let $f(n)$ be the largest positive integer $x$ less than ${10}^9$ such that the last 9 digits of $n^x$ form the number $x$ (including leading zeros), or zero if no such integer exists.
Lasse $f(n)$ die größte positive ganze Zahl $x$ kleiner als ${10}^9$ sein, so dass die letzten 9 Ziffern von $n^x$ die Zahl $x$ (einschließlich führender Nullen) bilden, oder Null, wenn es keine solche ganze Zahl gibt.
For example:
Zum Beispiel:
$$\begin{align} & f(4) = 411\\,728\\,896 (4^{411\\,728\\,896} = ...490\underline{411728896}) \\\\
& f(10) = 0 \\\\ & f(157) = 743\\,757 (157^{743\\,757} = ...567\underline{000743757}) \\\\
& Σf(n), 2 ≤ n ≤ 103 = 442\\,530\\,011\\,399 \end{align}$$
Find $\sum f(n)$, $2 ≤ n ≤ {10}^6$.
Finde $\summe f(n)$, $2 ≤ n ≤ {10}^6$.
# --hints--
`powersWithTrailingDigits()` should return `450186511399999`.
`powersWithTrailingDigits()` sollte `450186511399999` zurückgeben.
```js
assert.strictEqual(powersWithTrailingDigits(), 450186511399999);

14
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-456-triangles-containing-the-origin-ii.md
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---
id: 5900f5351000cf542c510047
title: 'Problem 456: Triangles containing the origin II'
title: 'Problem 456: Dreiecke, die den Ursprung enthalten II'
challengeType: 1
forumTopicId: 302130
dashedName: problem-456-triangles-containing-the-origin-ii
@@ -8,25 +8,25 @@ dashedName: problem-456-triangles-containing-the-origin-ii
# --description--
Define:
Definiere:
$$\begin{align} & x_n = ({1248}^n\bmod 32323) - 16161 \\\\
& y_n = ({8421}^n\bmod 30103) - 15051 \\\\ & P_n = \\{(x_1, y_1), (x_2, y_2), \ldots, (x_n, y_n)\\} \end{align}$$
For example, $$P_8 = \\{(-14913, -6630), (-10161, 5625), (5226, 11896), (8340, -10778), (15852, -5203), (-15165, 11295), (-1427, -14495), (12407, 1060)\\}$$
Beispielsweise: $$P_8 = \\{(-14913, -6630), (-10161, 5625), (5226, 11896), (8340, -10778), (15852, -5203), (-15165, 11295), (-1427, -14495), (12407, 1060)\\}$$
Let $C(n)$ be the number of triangles whose vertices are in $P_n$ which contain the origin in the interior.
Lasse $C(n)$ die Anzahl der Dreiecke, deren Scheitelpunkte in $P_n$ liegen und die den Ursprung im Inneren enthalten, sein.
Examples:
Beispiele:
$$\begin{align} & C(8) = 20 \\\\
& C(600) = 8\\,950\\,634 \\\\ & C(40\\,000) = 2\\,666\\,610\\,948\\,988 \end{align}$$
Find $C(2\\,000\\,000)$.
Finde $C(2\\,000\\,000)$.
# --hints--
`trianglesContainingOriginTwo()` should return `333333208685971500`.
`trianglesContainingOriginTwo()` sollte `333333208685971500` zurückgeben.
```js
assert.strictEqual(trianglesContainingOriginTwo(), 333333208685971500);

14
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-457-a-polynomial-modulo-the-square-of-a-prime.md
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---
id: 5900f5361000cf542c510048
title: 'Problem 457: A polynomial modulo the square of a prime'
title: 'Problem 457: Ein Polynom modulo des Quadrats einer Primzahl'
challengeType: 1
forumTopicId: 302131
dashedName: problem-457-a-polynomial-modulo-the-square-of-a-prime
@@ -8,19 +8,19 @@ dashedName: problem-457-a-polynomial-modulo-the-square-of-a-prime
# --description--
Let $f(n) = n^2 - 3n - 1$.
Lasse $f(n) = n^2 - 3n - 1$ sein.
Let $p$ be a prime.
Lasse $p$ eine Primzahl sein.
Let $R(p)$ be the smallest positive integer $n$ such that $f(n)\bmod p^2 = 0$ if such an integer $n$ exists, otherwise $R(p) = 0$.
Lasse $R(p)$ die kleinste positive ganze Zahl $n$ sein, so dass $f(n)\bmod p^2 = 0$ ist, wenn ein solcher Integer $n$ existiert, andernfalls $R(p) = 0$.
Let $SR(L)$ be $\sum R(p)$ for all primes not exceeding $L$.
Lasse $SR(L)$ $\sum R(p)$ für alle Primzahlen sein, die $L$ nicht übersteigen.
Find $SR({10}^7)$.
Finde $SR({10}^7)$.
# --hints--
`polynomialModuloSquareOfPrime()` should return `2647787126797397000`.
`polynomialModuloSquareOfPrime()` sollte `2647787126797397000` zurückgeben.
```js
assert.strictEqual(polynomialModuloSquareOfPrime(), 2647787126797397000);

10
curriculum/challenges/german/10-coding-interview-prep/project-euler/problem-458-permutations-of-project.md
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---
id: 5900f5361000cf542c510049
title: 'Problem 458: Permutations of Project'
title: 'Problem 458: Permutationen des Projekts'
challengeType: 1
forumTopicId: 302132
dashedName: problem-458-permutations-of-project
@@ -8,17 +8,17 @@ dashedName: problem-458-permutations-of-project
# --description--
Consider the alphabet $A$ made out of the letters of the word `project`: $A = \\{c, e, j, o, p, r, t\\}$.
Betrachte das Alphabet $A$, das aus den Buchstaben des Wortes `project` besteht: $A = \\{c, e, j, o, p, r, t\\}$.
Let $T(n)$ be the number of strings of length $n$ consisting of letters from $A$ that do not have a substring that is one of the 5040 permutations of `project`.
Lasse $T(n)$ die Anzahl der Strings der Länge $n$ sein, die aus Buchstaben von $A$ bestehen, die keinen Unterstring haben, die eine der 5040 Permutationen von `project` ist.
$T(7) = 7^7 - 7! = 818\\,503$.
Find $T({10}^{12})$. Give the last 9 digits of your answer.
Finde $T({10}^{12})$. Gebe die letzten 9 Ziffern deiner Antwort an.
# --hints--
`permutationsOfProject()` should return `423341841`.
`permutationsOfProject()` sollte `423341841` zurückgeben.
```js
assert.strictEqual(permutationsOfProject(), 423341841);

2
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---
id: 6145ed1f22caab087630aaad
title: Step 34
title: Schritt 34
challengeType: 0
dashedName: step-34
---

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---
id: 6145f02240ff8f09f7ec913c
title: Step 36
title: Schritt 36
challengeType: 0
dashedName: step-36
---

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---
id: 6145f14f019a4b0adb94b051
title: Step 37
title: Schritt 37
challengeType: 0
dashedName: step-37
---

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---
id: 6145f685797bd30df9784e8c
title: Step 41
title: Schritt 41
challengeType: 0
dashedName: step-41
---
@@ -35,7 +35,7 @@ You should give the submit a `type` of `submit`.
assert.exists(document.querySelector('button[type="submit"]') || document.querySelector('form > input[type="submit"]'));
```
The submit should display the text `Send`.
Das Absenden sollte den Text `Send` anzeigen.
```js
assert.equal(document.querySelector('button[type="submit"]')?.textContent ?? document.querySelector('input[type="submit"]')?.value, 'Send');

2
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---
id: 6145f829ac6a920ebf5797d7
title: Step 42
title: Schritt 42
challengeType: 0
dashedName: step-42
---

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---
id: 6145f8f8bcd4370f6509078e
title: Step 43
title: Schritt 43
challengeType: 0
dashedName: step-43
---

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id: 6145fb5018cb5b100cb2a88c
title: Step 44
title: Schritt 44
challengeType: 0
dashedName: step-44
---

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---
id: 6145fc3707fc3310c277f5c8
title: Step 45
title: Schritt 45
challengeType: 0
dashedName: step-45
---

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id: 614796cb8086be482d60e0ac
title: Step 46
title: Schritt 46
challengeType: 0
dashedName: step-46
---

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id: 6147a14ef5668b5881ef2297
title: Step 47
title: Schritt 47
challengeType: 0
dashedName: step-47
---

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id: 614878f7a412310647873015
title: Step 48
title: Schritt 48
challengeType: 0
dashedName: step-48
---

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---
id: 61487b77d4a37707073a64e5
title: Step 49
title: Schritt 49
challengeType: 0
dashedName: step-49
---

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---
id: 61487da611a65307e78d2c20
title: Step 50
title: Schritt 50
challengeType: 0
dashedName: step-50
---

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---
id: 61487f703571b60899055cf9
title: Step 51
title: Schritt 51
challengeType: 0
dashedName: step-51
---

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---
id: 614880dc16070e093e29bc56
title: Step 52
title: Schritt 52
challengeType: 0
dashedName: step-52
---

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---
id: 614883b6fa720e09fb167de9
title: Step 53
title: Schritt 53
challengeType: 0
dashedName: step-53
---

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---
id: 614884c1f5d6f30ab3d78cde
title: Step 54
title: Schritt 54
challengeType: 0
dashedName: step-54
---

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---
id: 61488ecfd05e290b5712e6da
title: Step 55
title: Schritt 55
challengeType: 0
dashedName: step-55
---

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---
id: 6148d99cdc7acd0c519862cb
title: Step 56
title: Schritt 56
challengeType: 0
dashedName: step-56
---

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---
id: 6148da157cc0bd0d06df5c0a
title: Step 57
title: Schritt 57
challengeType: 0
dashedName: step-57
---
@@ -9,7 +9,7 @@ dashedName: step-57
To align the input boxes with each other, create a new ruleset that targets all `input` and `label` elements within an `.info` element and set the `display` property to `inline-block`.
Also, align the `label` element's text to the right.
Richte außerdem den Text des `label`-Elements nach rechts aus.
# --hints--

2
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---
id: 6148dc095264000dce348bf5
title: Step 58
title: Schritt 58
challengeType: 0
dashedName: step-58
---

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id: 6148dcaaf2e8750e6cb4501a
title: Step 59
title: Schritt 59
challengeType: 0
dashedName: step-59
---

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---
id: 6148dd31d210990f0fb140f8
title: Step 60
title: Schritt 60
challengeType: 0
dashedName: step-60
---

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---
id: 6148defa9c01520fb9d178a0
title: Step 61
title: Schritt 61
challengeType: 0
dashedName: step-61
---

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---
id: 6148e0bcc13efd10f7d7a6a9
title: Step 63
title: Schritt 63
challengeType: 0
dashedName: step-63
---

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---
id: 6148e161ecec9511941f8833
title: Step 64
title: Schritt 64
challengeType: 0
dashedName: step-64
---

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---
id: 6148e28706b34912340fd042
title: Step 65
title: Schritt 65
challengeType: 0
dashedName: step-65
---

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---
id: 6148e335c1edd512d00e4691
title: Step 66
title: Schritt 66
challengeType: 0
dashedName: step-66
---

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---
id: 6148e41c728f65138addf9cc
title: Step 67
title: Schritt 67
challengeType: 0
dashedName: step-67
---
# --description--
Certain types of motion-based animations can cause discomfort for some users. In particular, people with <dfn>vestibular</dfn> disorders have sensitivity to certain motion triggers.
Bestimmte Arten von bewegungsbasierten Animationen können einigen Benutzern Unbehagen bereiten. In particular, people with <dfn>vestibular</dfn> disorders have sensitivity to certain motion triggers.
The `@media` at-rule has a media feature called `prefers-reduced-motion` to set CSS based on the user's preferences. It can take one of the following values:

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---
id: 6148e5aeb102e3142de026a2
title: Step 68
title: Schritt 68
challengeType: 0
dashedName: step-68
---

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---
id: 6351e7a8684bf5377c4ee7f7
title: Step 31
title: Schritt 31
challengeType: 0
dashedName: step-31
---
@@ -39,7 +39,7 @@ const htmlFor = document.querySelectorAll('ul.answers-list > li > label')?.[1]?.
assert.equal(htmlFor, document.querySelectorAll('ul.answers-list > li > label > input')?.[1]?.id);
```
You should give the third `label` a `for` attribute.
Du solltest dem dritten `label` ein `for`-Attribut geben.
```js
assert.notEmpty(document.querySelectorAll('ul.answers-list > li > label')?.[2]?.htmlFor);

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curriculum/challenges/german/14-responsive-web-design-22/learn-basic-css-by-building-a-cafe-menu/5f332a88dc25a0fd25c7687a.md
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# --description--
The name of the cafe is `CAMPER CAFE`. Add an `h1` element within your `main` element. Give it the name of the cafe in capitalized letters to make it stand out.
The name of the cafe is `CAMPER CAFE`. Add an `h1` element within your `main` element. Gib den Namen des Cafés in Großbuchstaben an, um ihn hervorzuheben.
# --hints--
@@ -17,13 +17,13 @@ You should have an opening `<h1>` tag.
assert(code.match(/<h1>/i));
```
You should have a closing `</h1>` tag.
Du solltest ein schließendes `</h1>`-Tag haben.
```js
assert(code.match(/<\/h1>/i));
```
You should not change your existing `main` element.
Du solltest dein bestehendes `main`-Element nicht ändern.
```js
assert($('main').length === 1);
@@ -35,7 +35,7 @@ Your `h1` element should be nested in your `main` element.
assert($('h1')[0].parentElement.tagName === "MAIN");
```
Your `h1` element should have the text `CAMPER CAFE`.
Dein `h1`-Element sollte den Text `CAMPER CAFE` enthalten.
```js
assert(code.match(/<h1>CAMPER CAFE<\/h1>/));

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---
id: 5f344f9c805cd193c33d829c
title: Step 11
title: Schritt 11
challengeType: 0
dashedName: step-11
---

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---
id: 5f344fad8bf01691e71a30eb
title: Step 10
title: Schritt 10
challengeType: 0
dashedName: step-10
---

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id: 5f344fbc22624a2976425065
title: Step 9
title: Schritt 9
challengeType: 0
dashedName: step-9
---

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---
id: 5f344fc1520b6719f2e35605
title: Step 8
title: Schritt 8
challengeType: 0
dashedName: step-8
---

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---
id: 5f3477ae34c1239cafe128be
title: Step 13
title: Schritt 13
challengeType: 0
dashedName: step-13
---

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---
id: 5f3477ae8466a9a3d2cc953c
title: Step 15
title: Schritt 15
challengeType: 0
dashedName: step-15
---

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---
id: 5f3477ae9675db8bb7655b30
title: Step 12
title: Schritt 12
challengeType: 0
dashedName: step-12
---
@@ -18,21 +18,21 @@ const hasH1 = new __helpers.CSSHelp(document).getStyle('h1');
assert(hasH1);
```
You should not add a new `style` tag. Add the new CSS rules to the existing `style` tag.
Du solltest kein neues `style`-Tag hinzufügen. Add the new CSS rules to the existing `style` tag.
```js
const hasManyStyleTags = document.querySelectorAll('style').length > 1;
assert(!hasManyStyleTags);
```
You should add a new `h2` selector.
Du solltest einen neuen `h2`-Selektor hinzufügen.
```js
const hasH2 = new __helpers.CSSHelp(document).getStyle('h2');
assert(hasH2);
```
You should add a new `p` selector.
Du solltest einen neuen `p`-Selektor hinzufügen.
```js
const hasP = new __helpers.CSSHelp(document).getStyle('p');

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id: 5f3477aefa51bfc29327200b
title: Step 14
title: Schritt 14
challengeType: 0
dashedName: step-14
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title: Schritt 16
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title: Schritt 18
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title: Schritt 17
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title: Schritt 19
challengeType: 0
dashedName: step-19
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id: 5f356ed60a5decd94ab66986
title: Step 22
title: Schritt 22
challengeType: 0
removeComments: false
dashedName: step-22

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title: Schritt 26
challengeType: 0
dashedName: step-26
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title: Schritt 21
challengeType: 0
dashedName: step-21
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title: Schritt 23
challengeType: 0
dashedName: step-23
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title: Step 25
title: Schritt 25
challengeType: 0
dashedName: step-25
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title: Schritt 27
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title: Schritt 20
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title: Schritt 29
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title: Schritt 28
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title: Schritt 38
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title: Schritt 32
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title: Schritt 31
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title: Schritt 30
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title: Schritt 37
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title: Schritt 39
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title: Schritt 36
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title: Schritt 41
challengeType: 0
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title: Schritt 42
challengeType: 0
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title: Schritt 46
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title: Schritt 40
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title: Schritt 66
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title: Schritt 56
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title: Schritt 55
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title: Schritt 54
challengeType: 0
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title: Schritt 58
challengeType: 0
dashedName: step-58
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id: 5f3ef6e06d34faac0447fc44
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title: Schritt 60
challengeType: 0
dashedName: step-60
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id: 5f3ef6e07276f782bb46b93d
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title: Schritt 63
challengeType: 0
dashedName: step-63
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id: 5f3ef6e0819d4f23ca7285e6
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title: Schritt 48
challengeType: 0
dashedName: step-48
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title: Schritt 61
challengeType: 0
dashedName: step-61
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title: Schritt 59
challengeType: 0
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title: Schritt 53
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title: Step 62
title: Schritt 62
challengeType: 0
dashedName: step-62
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title: Step 67
title: Schritt 67
challengeType: 0
dashedName: step-67
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title: Step 68
title: Schritt 68
challengeType: 0
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id: 5f459a7ceb8b5c446656d88b
title: Step 69
title: Schritt 69
challengeType: 0
dashedName: step-69
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id: 5f459cf202c2a3472fae6a9f
title: Step 70
title: Schritt 70
challengeType: 0
dashedName: step-70
---

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id: 5f459fd48bdc98491ca6d1a3
title: Step 71
title: Schritt 71
challengeType: 0
dashedName: step-71
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id: 5f45a05977e2fa49d9119437
title: Step 72
title: Schritt 72
challengeType: 0
dashedName: step-72
---

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---
id: 5f45a5a7c49a8251f0bdb527
title: Step 74
title: Schritt 74
challengeType: 0
dashedName: step-74
---
# --description--
Verwende den gleichen Stil-Selektor wie im vorherigen Schritt, um die Schriftgröße der Artikel und Preise zu vergrößern, indem du einen Wert von `18px` verwendest.
Using the same style selector in the previous step, make the font size of the items and prices larger by using a value of `18px`.
# --hints--

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title: Schritt 78
challengeType: 0
dashedName: step-78
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title: Schritt 79
challengeType: 0
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