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fix(curriculum): break down cipher project step 13 (#54472)

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Co-authored-by: Naomi <nhcarrigan@gmail.com>
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Sanskriti
2024-04-24 23:43:14 +05:30
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parent e1ffdbcaf8
commit 839bbadc64
998 changed files with 1557 additions and 1156 deletions
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curriculum/challenges/_meta/learn-string-manipulation-by-building-a-cipher/meta.json
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@@ -64,332 +64,336 @@
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---
id: 6624e0ec0bf47017eed84b1f
title: Step 14
challengeType: 20
dashedName: step-14
---
# --description--
The first kind of cipher you are going to build is called a *Caesar* cipher. Specifically, you will take each letter in your message, find its position in the alphabet, take the letter located after 3 positions in the alphabet, and replace the original letter with the new letter.
To implement this, you will use the `.find()` method discussed in the previous step. Modify your existing `.find()` call passing it `text[0]` as the argument instead of `'z'`.
# --hints--
You should modify your existing `alphabet.find('z')` call passing `text[0]` to the method.
```js
assert.match(code, /^alphabet\.find\s*\(\s*text\s*\[\s*0\s*\]\s*\)/m)
```
# --seed--
## --seed-contents--
```py
--fcc-editable-region--
text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
alphabet.find('z')
--fcc-editable-region--
```

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title: Step 17
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title: Step 20
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title: Step 22
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title: Step 27
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title: Step 28
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title: Step 30
challengeType: 20
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title: Step 34
challengeType: 20
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title: Step 35
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title: Step 36
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title: Step 29
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title: Step 37
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title: Step 40
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title: Step 42
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title: Step 43
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